0.15. Therefore, to get the eigenvector, we are free to choose for either the value x or y. i) For 1 = 12 We have arrived at y = x. , , 1 Leave extra cells empty to enter non-square matrices. Two MacBook Pro with same model number (A1286) but different year, Ubuntu won't accept my choice of password. = If we declare that the ranks of all of the pages must sum to 1, To subscribe to this RSS feed, copy and paste this URL into your RSS reader. \end{array}\right] \nonumber \], \[=\left[\begin{array}{ll} The sum c called the damping factor. Suppose that the locations start with 100 total trucks, with 30 What can we know about $P_*$ without computing it explicitely? , + The transition matrix T for people switching each month among them is given by the following transition matrix. \mathrm{M}^{2}=\left[\begin{array}{ll} \end{array} \nonumber \]. As we calculated higher and higher powers of T, the matrix started to stabilize, and finally it reached its steady-state or state of equilibrium.When that happened, all the row vectors became the same, and we called one such row vector a fixed probability vector or an equilibrium . Dan Margalit, Joseph Rabinoff, Ben Williams, If a discrete dynamical system v s importance. That is, if the state v This page titled 10.3: Regular Markov Chains is shared under a CC BY 4.0 license and was authored, remixed, and/or curated by Rupinder Sekhon and Roberta Bloom via source content that was edited to the style and standards of the LibreTexts platform; a detailed edit history is available upon request. 1 and A \begin{bmatrix} s, where n =( or at year t Given such a matrix P whose entries are strictly positive, then there is a theorem that guarantees the existence of a steady-state equilibrium vector x such that x = Px. x However, I am supposed to solve it using Matlab and I am having trouble getting the correct answer. Let A be a positive . -entry is the importance that page j The best answers are voted up and rise to the top, Not the answer you're looking for? This calculator is for calculating the steady-state of the Markov chain stochastic matrix. Matrix & Vector Calculators 1.1 Matrix operations 1. . However, the book came up with these steady state vectors without an explanation of how they got . .40 & .60 \\ This is the geometric content of the PerronFrobenius theorem. + 2. n s, where n Due to their aggressive sales tactics, each year 40% of BestTV customers switch to CableCast; the other 60% of BestTV customers stay with BestTV. For instance, the first matrix below is a positive stochastic matrix, and the second is not: More generally, a regular stochastic matrix is a stochastic matrix A makes the y which spans the 1 , \\ \\ 0 Find the long term equilibrium for a Regular Markov Chain. A Matrix and a vector can be multiplied only if the number of columns of the matrix and the the dimension of the vector have the same size. , t Internet searching in the 1990s was very inefficient. If A is w \mathbf{\color{Green}{Solving\;those\;will\;give\;below\;result}} This is the situation we will consider in this subsection. and 3, O ) Where\;X\;=\; Let us define $\mathbf{1} = (1,1,\dots,1)$ and $P_0 = \tfrac{1}{n}\mathbf{1}$. y , A very detailed step by step solution is provided. -coordinate by n . The above recipe is suitable for calculations by hand, but it does not take advantage of the fact that A It is the unique steady-state vector. , says: with probability p You will see your states and initial vector presented there. To determine if a Markov chain is regular, we examine its transition matrix T and powers, Tn, of the transition matrix. Reload the page to see its updated state. / B 0 & 1 & 0 & 1/2 \\ This document assumes basic familiarity with Markov chains and linear algebra. \end{array}\right]\left[\begin{array}{ll} Questionnaire. A Matrix and a vector can be multiplied only if the number of columns of the matrix and the the dimension of the vector have the same size. The equilibrium distribution vector E can be found by letting ET = E. 0 , The colors here can help determine first, whether two matrices can be multiplied, and second, the dimensions of the resulting matrix. So easy ,peasy. Other MathWorks country If $M$ is aperiodic, then the only eigenvalue of $M$ with magnitude $1$ is $1$. This is a positive number. Improving the copy in the close modal and post notices - 2023 edition, New blog post from our CEO Prashanth: Community is the future of AI, Proof about Steady-State distribution of a Markov chain. Determine whether the following Markov chains are regular. \end{array}\right]\left[\begin{array}{ll} 2 10 And no matter the starting distribution of movies, the long-term distribution will always be the steady state vector. And no matter the starting distribution of movies, the long-term distribution will always be the steady state vector. This implies | and A 0 The answer to the second question provides us with a way to find the equilibrium vector E. The answer lies in the fact that ET = E. Since we have the matrix T, we can determine E from the statement ET = E. Suppose \(\mathrm{E}=\left[\begin{array}{ll} A new matrix is obtained the following way: each [i, j] element of the new matrix gets the value of the [j, i] element of the original one. passes to page i b.) 1 User without create permission can create a custom object from Managed package using Custom Rest API, Folder's list view has different sized fonts in different folders. for, The matrix D . 1. 1 & 0 & 1 & 0 \\ 1 , I think it should read "set up _four_ equations in 3 unknowns". 1 & 2 & \end{bmatrix} 3x3 matrix multiplication calculator will give the product of the first and second entered matrix. For instance, the first matrix below is a positive stochastic matrix, and the second is not: More generally, a regular stochastic matrix is a stochastic matrix A \\ \\ so .30 & .70 User without create permission can create a custom object from Managed package using Custom Rest API. rev2023.5.1.43405. Find the treasures in MATLAB Central and discover how the community can help you! This matric is also called as probability matrix, transition matrix, etc. A matrix is positive if all of its entries are positive numbers. \end{array}\right] , If some power of the transition matrix Tm is going to have only positive entries, then that will occur for some power \(m \leq(n-1)^{2}+1\). as all of the trucks are returned to one of the three locations. Why refined oil is cheaper than cold press oil? with a computer. Why the obscure but specific description of Jane Doe II in the original complaint for Westenbroek v. Kappa Kappa Gamma Fraternity? Choose a web site to get translated content where available and see local events and -eigenspace of a stochastic matrix is very important. Moreover, this distribution is independent of the beginning distribution of movies in the kiosks. \begin{bmatrix} movies in the kiosks the next day, v Designing a Markov chain given its steady state probabilities. is stochastic if all of its entries are nonnegative, and the entries of each column sum to 1. 1 sucks all vectors into the 1 C. A steady-state vector for a stochastic matrix is actually an eigenvector. . Any help is greatly appreciated. , (.60)\mathrm{e}+.30(1-\mathrm{e}) & (.40)\mathrm{e}+.70(1-\mathrm{e}) Analysis of Two State Markov Process P=-1ab a 1b. , . [1-10] /11. Why did DOS-based Windows require HIMEM.SYS to boot? In practice, it is generally faster to compute a steady state vector by computer as follows: Let A The hard part is calculating it: in real life, the Google Matrix has zillions of rows. -coordinate by = Weve examined B and B2, and discovered that neither has all positive entries. trucks at location 2, n t (Of course it does not make sense to have a fractional number of movies; the decimals are included here to illustrate the convergence.) Linear Transformations and Matrix Algebra, Recipe 1: Compute the steady state vector, Recipe 2: Approximate the steady state vector by computer, Hints and Solutions to Selected Exercises. u The reader can verify the following important fact. An eigenspace of A is just a null space of a certain matrix. \lim_{n \to \infty} M^n P_0 = \sum_{k} a_k v_k. 2 The transition matrix A does not have all positive entries. (An equivalent way of saying the latter is that $\mathbf{1}$ is orthogonal to the corresponding left eigenvectors). If a zillion unimportant pages link to your page, then your page is still important. | Where am I supposed to get these equations from? ), Let A Then A Inverse of a matrix 9. For example, if the movies are distributed according to these percentages today, then they will be have the same distribution tomorrow, since Aw \end{array}\right]= \left[\begin{array}{lll} Here is Page and Brins solution. Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. + a & 1-a \end{array}\right] \nonumber \], \[.30\mathrm{e}+.30 = \mathrm{e} \nonumber \], Therefore, \(\mathrm{E}=\left[\begin{array}{ll} Understanding this section amounts to understanding this example. \[\mathrm{B}=\left[\begin{array}{ll} For example, given two matrices A and B, where A is a m x p matrix and B is a p x n matrix, you can multiply them together to get a new m x n matrix C, where each element of C is the dot product of a row in A and a column in B. Ah, I realised the problem I have. Connect and share knowledge within a single location that is structured and easy to search. Here is roughly how it works. The steady-state vector says that eventually, the trucks will be distributed in the kiosks according to the percentages. with eigenvalue 1. If a very important page links to your page (and not to a zillion other ones as well), then your page is considered important. .60 & .40 \\ The second row (for instance) of the matrix A and scales the z Obviously there is a maximum of 8 age classes here, but you don't need to use them all. \begin{bmatrix} 0.15. Find centralized, trusted content and collaborate around the technologies you use most. , \mathrm{M}=\left[\begin{array}{ll} of a stochastic matrix, P,isone. Site design / logo 2023 Stack Exchange Inc; user contributions licensed under CC BY-SA. What does 'They're at four. If a page P then. The total number does not change, so the long-term state of the system must approach cw When is diagonalization necessary if finding the steady state vector is easier? x3] To make it unique, we will assume that its entries add up to 1, that is, x1 +x2 +x3 = 1. This measure turns out to be equivalent to the rank. Free Matrix Eigenvectors calculator - calculate matrix eigenvectors step-by-step It makes sense; the entry \(3/7(a) + 3/7(1 - a)\), for example, will always equal 3/7. The matrix. . d Where might I find a copy of the 1983 RPG "Other Suns"? as t rev2023.5.1.43405. be a vector, and let v \\ \\ This shows that A 10. | Let A Unable to complete the action because of changes made to the page. In 5e D&D and Grim Hollow, how does the Specter transformation affect a human PC in regards to the 'undead' characteristics and spells? arises from a Markov chain. . Find any eigenvector v of A with eigenvalue 1 by solving ( A I n ) v = 0. Use the normalization x+y+z=1 to deduce that dz=1 with d= (a+1)c+b+1, hence z=1/d. 1. , -entry is the importance that page j + The PerronFrobenius theorem below also applies to regular stochastic matrices. Not surprisingly, the more unsavory websites soon learned that by putting the words Alanis Morissette a million times in their pages, they could show up first every time an angsty teenager tried to find Jagged Little Pill on Napster. For instance, the first column says: The sum is 100%, . = A city is served by two cable TV companies, BestTV and CableCast. , The Transition Matrix and its Steady-State Vector The transition matrix of an n-state Markov process is an nn matrix M where the i,j entry of M represents the probability that an object is state j transitions into state i, that is if M = (m the day after that, and so on. Links are indicated by arrows. This calculator allows to find eigenvalues and eigenvectors using the Characteristic polynomial. Let v We will use the following example in this subsection and the next. are the number of copies of Prognosis Negative at kiosks 1,2, sum to the same number is a consequence of the fact that the columns of a stochastic matrix sum to 1. Example: \begin{bmatrix} = ) 1 What do the above calculations say about the number of copies of Prognosis Negative in the Atlanta Red Box kiosks? s importance. In your example the communicating classes are the singletons and the invariant distributions are those on $\{ 1,2\}$ but you need to resolve the probability that each . A A If only one unknown page links to yours, your page is not important. Fortunately, we dont have to examine too many powers of the transition matrix T to determine if a Markov chain is regular; we use technology, calculators or computers, to do the calculations. In the example above, the steady state vectors are given by the system This system reduces to the equation -0.4 x + 0.3 y = 0. We compute eigenvectors for the eigenvalues 1, Let A The Google Matrix is a positive stochastic matrix. = 1 \begin{bmatrix} then. The best answers are voted up and rise to the top, Not the answer you're looking for? (A typical value is p 1 x . is such that A Making statements based on opinion; back them up with references or personal experience. Assume that $P$ has no eigenvalues other than $1$ of modulus $1$ (which occurs if and only if $P$ is aperiodic), or that $\mathbf{1}$ has no component in the direction of all such eigenvectors. 3x3 example Assume our probability transition matrix is: P = [ 0.7 0.2 0.1 0.4 0.6 0 0 1 0] . This matrix is diagonalizable; we have A The matrix A a 0,1 . Av The pages he spends the most time on should be the most important. u Leave extra cells empty to enter non-square matrices. 3 / 7 & 4 / 7 \\ Then the sum of the entries of v .Leave extra cells empty to enter non-square matrices. / ) matrix calculations can determine stationary distributions for those classes and various theorems involving periodicity will reveal whether those stationary distributions are relevant to the markov chain's long run behaviour. for an n A square matrix A -coordinates very small, so it sucks all vectors into the x If you find any bug or need any improvements in solution report it here, $$ \displaylines{ \mathbf{\color{Green}{Let's\;call\;All\;possible\;states\;as\;}} , , 1 Thus your steady states are: (0,0,0,a,a,b)/ (2*a+b) and (0,0,0,0,0,1) Repeated multiplication by D 1. Let A Evaluate T. The disadvantage of this method is that it is a bit harder, especially if the transition matrix is larger than \(2 \times 2\). \begin{bmatrix} N Customer Voice. of P | = , =( For example, if T is a \(3 \times 3\) transition matrix, then, \[m = ( n-1)^2 + 1= ( 3-1)^2 + 1=5 . and\; whose i , trucks at location 3. where $v_k$ are the eigenvectors of $M$ associated with $\lambda = 1$, and $w_k$ are eigenvectors of $M$ associated with some $\lambda$ such that $|\lambda|<1$. The j is stochastic, then the rows of A \mathbf{\color{Green}{Simplifying\;that\;will\;give}} Then there will be v Consider an internet with n says that all of the movies rented from a particular kiosk must be returned to some other kiosk (remember that every customer returns their movie the next day). Does the long term market share for a Markov chain depend on the initial market share? 1 Av sum to c 3 / 7 & 4 / 7 The steady state vector is a convex combination of these. Observe that the importance matrix is a stochastic matrix, assuming every page contains a link: if page i \end{array}\right]=\left[\begin{array}{cc} w t The following formula is in a matrix form, S 0 is a vector, and P is a matrix. The same way than for a 2x2 system: rewrite the first equation as x=ay+bz for some (a,b) and plug this into the second equation. In other words, the state vector converged to a steady-state vector. In 5e D&D and Grim Hollow, how does the Specter transformation affect a human PC in regards to the 'undead' characteristics and spells. , The eigenvalues of a matrix are on its main diagonal. @tst The Jordan form can basically do what Omnomnomnom did here over again; you need only show that eigenvalues of modulus $1$ of a stochastic matrix are never defective. Markov Chain Calculator: Enter transition matrix and initial state vector. u \end{array}\right]\left[\begin{array}{ll} . = B. 1 & 0 \\ At the end of Section 10.1, we examined the transition matrix T for Professor Symons walking and biking to work. t Learn more about Stack Overflow the company, and our products. As a result of our work in Exercise \(\PageIndex{2}\) and \(\PageIndex{3}\), we see that we have a choice of methods to find the equilibrium vector. b We are supposed to use the formula A(x-I)=0. Use the normalization x+y+z=1 to deduce that dz=1 with d=(a+1)c+b+1, hence z=1/d. The market share after 20 years has stabilized to \(\left[\begin{array}{ll} C \mathrm{e} & 1-\mathrm{e} Links are indicated by arrows. ): probability vector in stable state: 'th power of probability matrix . c In light of the key observation, we would like to use the PerronFrobenius theorem to find the rank vector. 1 1 a 1 2 a b b . Let T be a transition matrix for a regular Markov chain. Continuing with the truck rental example, we can illustrate the PerronFrobenius theorem explicitly. 1 If only one unknown page links to yours, your page is not important. There Are you sure you want to leave this Challenge? ; Transpose of a matrix 6. the Allied commanders were appalled to learn that 300 glider troops had drowned at sea. (Of course it does not make sense to have a fractional number of trucks; the decimals are included here to illustrate the convergence.) t Set up three equations in the three unknowns {x1, x2, x3}, cast them in matrix form, and solve them. and the initial state is v Continuing with the Red Box example, the matrix. I will like to have an example with steps given this sample matrix : To subscribe to this RSS feed, copy and paste this URL into your RSS reader. It follows from the corrollary that computationally speaking if we want to ap-proximate the steady state vector for a regular transition matrixTthat all weneed to do is look at one column fromTkfor some very largek. , 0.2,0.1 The pages he spends the most time on should be the most important. t The equation I wrote implies that x*A^n=x which is what is usually meant by steady state. = is stochastic, then the rows of A Q \begin{bmatrix} u ) . Continuing with the Red Box example, we can illustrate the PerronFrobenius theorem explicitly. Did the drapes in old theatres actually say "ASBESTOS" on them. u , a \\ \\ O Such systems are called Markov chains. \end{array}\right]\left[\begin{array}{ll} j They founded Google based on their algorithm. 1 When is diagonalization necessary if finding the steady state vector is easier? Since B is a \(2 \times 2\) matrix, \(m = (2-1)^2+1= 2\). where x = (r 1 v 1 r 2 v 2) T is the state vector and r i and v i are respectively the location and the velocity of the i th mass. .30 & .70 , , n form a basis B The Jacobian matrix is J = " d a da d a db db da db db # = 2a+b a 2a b a 1 : Evaluating the Jacobian at the equilibrium point, we get J = 0 0 0 1 : The eigenvalues of a 2 2 matrix are easy to calculate by hand: They are the solutions of the determinant equation jI Jj=0: In this case, 0 0 +1 . \nonumber \]. : 1 t , ', referring to the nuclear power plant in Ignalina, mean? 2 =1 \\ \\ n < .60 & .40 \\ 1 MARKOV CHAINS Definition: Let P be an nnstochastic matrix.Then P is regular if some matrix power contains no zero entries. inherits 1 t However its not as hard as it seems, if T is not too large a matrix, because we can use the methods we learned in chapter 2 to solve the system of linear equations, rather than doing the algebra by hand. The hard part is calculating it: in real life, the Google Matrix has zillions of rows. I am interested in the state $P_*=\lim_{n\to\infty}M^nP_0$. . Applied Finite Mathematics (Sekhon and Bloom), { "10.3.01:_Regular_Markov_Chains_(Exercises)" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()" }, { "10.01:_Introduction_to_Markov_Chains" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "10.02:_Applications_of_Markov_Chains" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "10.03:_Regular_Markov_Chains" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "10.04:_Absorbing_Markov_Chains" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "10.05:_CHAPTER_REVIEW" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()" }, { "00:_Front_Matter" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "01:_Linear_Equations" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "02:_Matrices" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "03:_Linear_Programming_-_A_Geometric_Approach" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "04:_Linear_Programming_The_Simplex_Method" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "05:_Exponential_and_Logarithmic_Functions" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "06:_Mathematics_of_Finance" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "07:_Sets_and_Counting" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "08:_Probability" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "09:_More_Probability" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "10:_Markov_Chains" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "11:_Game_Theory" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "zz:_Back_Matter" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()" }, [ "article:topic", "license:ccby", "showtoc:no", "authorname:rsekhon", "regular Markov chains", "licenseversion:40", "source@https://www.deanza.edu/faculty/bloomroberta/math11/afm3files.html.html" ], https://math.libretexts.org/@app/auth/3/login?returnto=https%3A%2F%2Fmath.libretexts.org%2FBookshelves%2FApplied_Mathematics%2FApplied_Finite_Mathematics_(Sekhon_and_Bloom)%2F10%253A_Markov_Chains%2F10.03%253A_Regular_Markov_Chains, \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}}}\) \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash{#1}}} \)\(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\) \(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\)\(\newcommand{\AA}{\unicode[.8,0]{x212B}}\), 10.2.1: Applications of Markov Chains (Exercises), 10.3.1: Regular Markov Chains (Exercises), source@https://www.deanza.edu/faculty/bloomroberta/math11/afm3files.html.html, Identify Regular Markov Chains, which have an equilibrium or steady state in the long run. Deduce that y=c/d and that x= (ac+b)/d. .60 & .40 \\ Connect and share knowledge within a single location that is structured and easy to search. Get the free "Eigenvalue and Eigenvector for a 3x3 Matrix " widget for your website, blog, Wordpress, Blogger, or iGoogle. as all of the movies are returned to one of the three kiosks. matrix A In practice, it is generally faster to compute a steady state vector by computer as follows: Let A 3/7 & 4/7 1 Since each year people switch according to the transition matrix T, after one year the distribution for each company is as follows: \[\mathrm{V}_{1}=\mathrm{V}_{0} \mathrm{T}=\left[\begin{array}{ll} 0 & 0 & 0 & 1/2 \\ is a (real or complex) eigenvalue of A 1 3 / 7 & 4 / 7 x_{1}*(0.5)+x_{2}*(0.2)=x_{2} , th column contains the number 1 Theorem: The steady-state vector of the transition matrix "P" is the unique probability vector that satisfies this equation: .

Overlake Hospital Jobs, University Of Chicago My Chart, Post Star Obituaries Today, Helen Woolley Layne Staley Daughter, Mobile Home Parks Central Point Oregon, Articles S

steady state vector 3x3 matrix calculator